# dp array sum

You might be asked to return the sum of an array between `i`

and `j`

, repeatedly. Computing sums is an `O(n)`

operation so a caching a solution optimizes the problem down to an `O(1)`

operation, once the cache has been populated:

```
1 from itertools import accumulate
2
3 nums = [*range(1, 10)]
4 acc = [*accumulate(nums)]
5
6 asum = lambda i, j: acc[j] - (0, acc[i - 1])[i > 0]
7
8 print(asum(1, 3))
```

The trick boils down to running an accumulate, and substracting the accumulated value at `i-1`

from the accumulated value at `j`

.

See also: